A 2-a editia a Batavia Amsterdam Chess Tournament, numita de asemenea the Max Euwe Challenge, are loc in perioada 19 – 28 February in Cafe Batavia 1920, in Amsterdam, Olanda.
La turneu participa si Alina Motoc, care a inceput foarte slab concursul.
| Rank | Name | Fed. | Rating | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | Score |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| 1 | Shiven, Khosla | IND | 2291 | x | ½ | 1 | 1 | 2.5 | ||||||
| 2 | IM Wemmers, Xander | NED | 2404 | x | ½ | 1 | 1 | 2.5 | ||||||
| 3 | WIM Schut, Lisa | NED | 2219 | x | 1 | 0 | 1 | 2.0 | ||||||
| 4 | IM Riemersma, Li | NED | 2431 | 0 | x | 1 | 1 | 2.0 | ||||||
| 5 | Vedder, Henk | NED | 2377 | ½ | ½ | x | ½ | 1.5 | ||||||
| 6 | FM Kleijn, Christov | NED | 2359 | 0 | ½ | x | 1 | 1.5 | ||||||
| 7 | Singh, Gurpreet Pal | IND | 2303 | 0 | x | ½ | 1 | 1.5 | ||||||
| 8 | FM Bezemer, Arno | NED | 2343 | 0 | 1 | 0 | x | 1.0 | ||||||
| 9 | WGM Motoc, Alina | ROU | 2349 | 0 | 0 | ½ | x | 0.5 | ||||||
| 10 | IM Afek, Yochanan | ISR | 2280 | 0 | 0 | 0 | x | 0.0 |
In runda a 3-a Alina Motoc a pierdut la WIM Lisa Schut (2219) in doar15 mutari, dupa o evolutie bizara:
Alina,Motoc (2349) – Lisa,Schut (2219) [A16]
Amsterdam (3), 22.02.2010
[AS]
1.Nf3 Nf6 2.c4 g6 3.Nc3 d5 4.cxd5 Nxd5 5.h4!?
O idee interesanta, cu scopul de a surprinde, dar daca Negrul se dezvolta principial si face rocada mare nu cred sa aiba probleme deosebite. 5…c5 [5…h5 6.e4 Nxc3 7.bxc3 Bg7 8.d4 c5 9.Be3 Nc6 10.Qd2 Bg4 11.d5 Qa5 12.Rc1 Rd8 13.Ng5 0–0 14.f3 Bc8 15.Bc4 e6 16.Bb3 exd5 17.Bxd5 c4 18.0–0 Ne7 19.Rfd1 Nxd5 20.exd5 Bf5 21.Ne4 Rfe8 22.Bg5 Rd7 23.Nf6+ Bxf6 24.Bxf6 Rd6 25.Bd4 f6 26.Qf4 Red8 27.Re1 Qxd5 28.Re7 Re6 29.Rc7 Rde8 30.Qh6 R6e7 31.Rxe7 Rxe7 32.Bxf6 Rh7 33.Bd4 Re7 34.Bf6 Rh7 35.Qf4 Rf7 36.Bd4 Re7 37.Qb8+ Kf7 38.Qh8 a6 39.a4 Qd6 40.Qg7+ Ke8 41.Qg8+ Kd7 42.Qxc4 Qg3 43.Bf2 Qd6 44.Qb3 Kc7 45.Rd1 Qe6 46.Bg3+ Kc8 47.Qb4 b6 48.Bf2 Rd7 49.Re1 Qd6 50.Qxb6 Qxb6 51.Bxb6 Rd2 52.a5 Rc2 53.Bd4 Ra2 54.Re5 Kd7 55.Rc5 Bd3 56.Rg5 Bf5 57.g4 hxg4 58.fxg4 Be4 59.Kf1 Bd3+ 60.Ke1 Re2+ 61.Kd1 Rg2 62.Be3 Be2+ 63.Ke1 Bxg4 64.Rxg6 Re2+ 65.Kf1 Rxe3 66.Rxg4 Rxc3 67.h5 Rc5 68.Rh4 Rxa5 69.h6 Rf5+ 1/2–1/2 Morozevich Alexander (2755) – Mamedyarov Shakhriyar (2752), Wch Blitz, 2007; 5…Bg7 6.h5 Nc6 7.g3 Bg4 8.h6 Bxc3 9.bxc3 Bxf3 10.exf3 Qd6 11.Be2 0–0–0 12.Qb3 f5 13.a4 e5 14.a5 e4 15.f4 Nf6 16.0–0 Ng4 17.Ba3 Qxd2 18.a6 Na5 19.axb7+ Kb8 20.Qb5 e3 21.Bc5 exf2+ 22.Rxf2 1–0 Piket Jeroen (2575) – Shirov Alexei (2710), Amber-rapid, 1998; 5…Nf6 6.d4 Bg7 7.e4 0–0 8.Be2 c5 9.d5 e6 (9…b5 10.e5 Ng4 11.Bxb5 Nd7 12.e6 fxe6 13.dxe6 Nde5 14.Qxd8 Rxd8 15.Nxe5 Nxe5 16.0–0 a6 17.Be2 Bxe6 18.Re1 Bf7 19.Bf4 Nc6 20.Bf3 Rac8 21.Bg4 Ra8 22.Bf3 Rac8 23.Bg4 1/2–1/2 Zviaginsev Vadim (2671) – Najer Evgenly (2585), Aeroflot open, 2003) 10.h5 Nxh5 11.g4 Nf6 12.Bg5 Qb6 13.Bxf6 Bxf6 14.Qd2 Bg7 15.0–0–0 Nd7 16.g5 c4 17.Rh2 Re8 18.d6 Rd8 19.Qf4 Qa5 20.Rxh7 f5 21.gxf6 Nxf6 22.Rxg7+ Kxg7 23.e5 1–0 Piket Jeroen (2633) – Svidler, Peter (2672), Internet 2000; 5…Nxc3 6.bxc3 Bg7 7.g3 b6 8.Bg2 Bb7 9.h5 Nc6 10.Qa4 Qd7 11.Rb1 0–0–0 12.Ng5 e6 13.h6 Bf6 14.Nxf7 Qxf7 15.Bxc6 Rhf8 16.Bxb7+ Kxb7 17.Qe4+ Kb8 18.0–0 Bg5 19.d4 Bxc1 20.Rbxc1 Rd5 21.c4 Rh5 22.Rc3 Qf5 23.Qxf5 gxf5 24.Kg2 Rxh6 25.e3 Kb7 26.Kf3 Rg8 27.c5 Rf6 28.Rfc1 Rf7 29.a4 Rd8 30.Rb1 Ka6 31.cxb6 cxb6 32.a5 b5 33.Rc5 Rb7 34.Ra1 b4 35.Rc6+ Kb5 36.Rc5+ Ka6 37.Rc6+ Kb5 38.Rc5+ Ka6 1/2–1/2 Elijanov Pavel (2596) – Sutovsky Emil (2666), Geneve op, 2004] 6.h5 Bg7 [6…Nxc3 7.bxc3 Bg7 8.Rb1 Nc6 9.g3 b6 10.Bg2 Qd7 11.Qa4 Bb7 12.Kf1 e5 13.d3 Bf6 14.Bg5 Bxg5 15.Nxg5 0–0–0 16.Nxf7 Qxf7 17.Bxc6 Rhf8 18.Rb2 Qxf2# 0–1. Oms Pallise Josep (2440) – Wapner Jonathan (2325), Groningen op] 7.Qa4+?! Bd7 8.Qh4?!
Albul incearca sa justifice cele doua mutari de pioni cu inca doua mutari de dama, ramanand astfel in urma cu dezvoltarea. 8…Nb4! 9.hxg6 fxg6 Singurul lucru pe care l-a obtinut Albul este faptul ca Negrul a ramas cu 3 insule de pioni; dar acesta este un considerent secundar in aceasta pozitie. 10.Rb1 N8c6 Negrul mai are sa mute din dama si sa faca rocada mare si si-a incheiat dezvoltarea, pe cand Albul are nevoie de minim 5 mutari pentru a realiza acelasi lucru. 11.Qc4 Se ameninta 12.Rxh7 Rxh7 13. Qg8+, dar Albul a facut prea multe mutari din dama si o cauta cu lumanarea 11…Na5 12.Qxc5 Nc2+ 13.Kd1 Rc8
cu pretul unui pion Negrul a mai adus o piesa in joc, cu tempo. 14.Qd5?? [14.Qg5 mai prelungea lupta] 14…Bxc3 –+ 15.Rxh7 spera la 15…Rxh7??? 16.Qg8# [15.bxc3 Ne3+ 16.fxe3 Ba4+ –+; 15.dxc3 Ne3+ 16.Bxe3 Ba4+ –+] 15…Ne3+!
16.fxe3 Ba4+ si Albul pierde dama 0–1
